Type the correct answer in the box. Express your answer to three significant figures. The gas inside a large engine cylinder initially has a pressure of 105 kilopascals and a volume of 2.031 liters. If the gas is compressed at constant temperature to a volume of 0.356 liter, what is its new pressure?

The pressure of the compressed gas is
kilopascals.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

17

step-by-step explanation:

51/3=17

thus 17 is your answer.

answer: 12,000

step-by-step explanation: first you ar e supposed to add. then multiply then subtract