At the end of a snow storm, Amelia saw there was a lot of snow on her front lawn. The temperature increased and the snow began to melt at a steady rate. After the storm, the snow started melting at a rate of 1.5 inches per hour and it is known that 4 hours after the storm ended, the depth of snow was down to 12 inches. Write an equation for S, in terms of t, representing the depth of snow on Amelia's lawn, in inches, t hours after the snow stopped falling.

The equation is;

S = 18 - 1.5t  

Step-by-step explanation:

From the question, we are made to know that the depth of the snow is S and the time taken to melt in hours is t

After 4 hours of melting, the snow depth is 12 inches  

Now, recall that the rate of melting is 1.5 inches/ hour  

So in the 4 hours, the amount of snow melted will be 1.5 * 4 = 6 inches  

So the total depth of the snow initially will be 6 + 12 = 18 inches  

So let’s write the equation;

S = 18 - 1.5t  

Where S is the depth of the snow after a particular number of hours t

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2