Please help me I’m on Plato edmentum, and just want to pass this stupid course activity. :) Vertex form of the equation of a horizontal parabola is given by x=1/4p(y-k)^2+h where (h, k) is the vertex of the parabola and the absolute value of P is the distance from the vertex to the focus which is also the distance from the vertex to the directrix. PART A :Mark the focus of the problem you were going to create at F(-5,2). Draw a vertical line that is eight units to the right of the focus. This line will be the directrix. what is the equation of the line?
PART B: construct a line that is perpendicular to the directrix and passes through the focus. This line will be the axis of symmetry of the parabola. what are the coordinates of the point of intersection, A, the axis of symmetry and the directrix of the parabola.
PART C: explain how you can locate the vertex, V, of the parabola with the given focus and directrix. Write the coordinates of the vertex.
PART D: which way will probably open? Explain.
PART E: how can you find the value of P? Is the value of P for your parabola positive or negative? Explain.
PART F: what is the value of P for your parabola?
PART G: based on your responses to parts C and E above write the equation of the parabola in vertex form.
PART H: construct a parabola using the parabola tool in Geogebra. Take a screenshot of your work save it and insert the image below.
PART I: once you have constructed the parabola use Geogebra to display it’s equation. In the space below rearrange the equation of the parabola shown in Geogebra, and check whether it matches the equation of the vertex form that you wrote in Part G.