A coin is tossed and -sided die numbered 1 through is rolled. Find the probability of tossing a and then rolling a number greater than .

Complete question :

A coin is tossed and a die is rolled. Find the probability of tossing a tail and then rolling a number greater than 2.

Answer : 1/3

Step-by-step explanation:

For a coin :

Sample space = (T, H)

Probability = required outcome / Total possible outcomes

Probability of tail, p(T) = 1 / 2 = 0.5

For a fair die:

Sample space = (1, 2, 3, 4, 5, 6)

Required outcome = number greater than 2 = (3, 4, 5, 6) = 4

P(number greater than 2) = 4/6 = 2/ 3

Hence, probability of a tail, then a number greater than 2 :

(1/2 * 2/3) = 2 /6 = 1/3

a variable is any characteristics, number, or quantity that can be measured or counted. a variable may also be called a data item. hope i !

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240