Janelle graphed a line through (−6, 5) that had a slope of −79. What is the y-coordinate of a point on the line that has an x-coordinate of 3?

The value of the y-coordinate is -706

Step-by-step explanation:

The equation of a straight line is;

y = mx + c

where m is slope and c is t-intercept

Given the slope, we can write the equation as;

y = -79x + c

we need to get c

Just put in the x and y values of the given point

X = -6 and y = 5

5 = -79(-6) + c

5 = 474 + c

c = 5-474 = -469

So the complete equation of the line would

be ;

y = -79x - 469

To get the y-coordinate of the point, just insert the x value into the equation;

y = -79(3) - 469

y = -237 - 469 = -706

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is