PLEASE HELP Use the graph of f(x) to explain the relationship
between the real zeros of f(x) and its intercept(s).

f(x) has one real zero at -2 because the graph of
the function has an intercept at (0, -2).
f(x) has two real zeros at -4 and -2 because the
graph of the function has intercepts at (-4,0) and (0,
-2).
f(x) has no real zeros because the graph of the
function does not pass through (0,0).
f(x) has one real zero at 4 because the graph of
the function has an intercept at (-4, 0).

a

step-by-step explanation:

strong negative correlation

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .

8

step-by-step explanation: