What is the equation of a line passing through the point (4,-1) and parallel to the line whose equation is 2y-x=8

9514 1404 393

  2y -x = -6

Step-by-step explanation:

You can use the same x- and y-coefficients. You just have to change the constant on the right. Put the point values into the left expression to see the new constant.

  2y -x = 2(-1)-(4) = -6

The parallel line is ...

  2y -x = -6

there are no figures how am i supposed to answer this question

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb