A fast-food restaurant has a cost of production C(x)=12x+114 and a revenue function R(x)=6x. When does the company start to turn a profit?

Profit is the difference between the revenue and cost functions

A production greater than 19 will turn a profit

From the question, we have:

So, the profit function is:

Substitute known values

Equate to 0

Collect like terms

Divide both sides by -6

The above equation means that: A production greater than 19 will turn a profit

Read more about profit functions at:

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Step-by-step explanation:

Given data

C(x)=12x+114

R(x)=6x.

The company will start to run on profit just when revenue equals the production cost, that is

C(x)=R(x)

equating the two expressions we have

12x+114=6x

solving for x we have

12x-6x+114=0

6x+114=0

6x=-114

x=-114/6

x=-19

Hence the company will start to run on proft when they start to produce above 19 items

all but the second one

step-by-step explanation:

cuz that one goes over 180

mark brainliest

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.