A state lottery game consists of choosing one card from each of the four suits in a standard deck of playing cards. (There are 13 cards in each suit.) Count the number of ways in which four cards, each of a different face value, can be chosen.
ways

17160

Step-by-step explanation:

first there are 13 options

then there are 13 - 1 that was chosen

then there are 13 - 2 that were chosen

then there are 13 - 3 that were chosen

so that's 13 options, then 12 options, then 11 options, and then 10 options

and in order to figure out all of the possibilties we mutiply the options so

13*12*11*10 = 17160

little further explaining of why this works:

we have a set of letters (3 in a set)

A B C

what are the possible combinations?

AB

AC

BC

BA

CA

CB

the answer is 6 which is also 3 * 2 * 1 = 6

HOPE THAT HELPS!1! ^_^

3 ft

step-by-step explanation:

since the triangle is right use pythagoras' identity to solve for a

the square on the hypotenuse is equal to the sum of the squares on the other two sides, that is

a² + 8² = ( )²

a² + 64 = 73 ( subtract 64 from both sides )

a² = 9 ( take the square root of both sides )

a = = 3

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2