Point Q' is the image of (-5,1) under a translation by 6 units to the right and 2 units down

The object coordinate Q is (-11,3 )

Step-by-step explanation:

The translation is given as : ( 6,-2 )

The image coordinates for Q' is ( -5,1 )

So, to get the coordinates of object point Q (x,y), will be;

 Q (x,y)  + ( 6,-2 )---translation ⇒image Q' ( -5,1 )

Thus,

x+6 = -5

x= -5-6= -11

and

y+ -2 = 1

y-2=1

y=1+2 =3

Thus the object point coordinates Q is (-11,3 )

c

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet