Determine if JK and LM are parallel, perpendicular, or neither in the following questions. 1) J(1,9), K(7,4), L(8,13), M (-2, 1)

2) J(13, -5), K(2, 6), L(-1, -5), M(-4, -2)

3) J(-10, -7), K(-4,1), L(-3, 2), M(-6, -2)

4) J(11 -2), K(3, -2), L(1, -7), M(1, -2),

i think it would be 42cm

25% is the answer

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source