A pair of parallel lines is cut by a transversal. What are the measures of the two marked angles? CHOICES

40 degrees and 40 degrees

40 degrees and 140 degrees

65 degrees and 115 degrees

75 degrees and 105 degrees

Let us mark the points R and S on line p, T and U on line q, A and B on line l and C and D on line m.

Suppose the lines p and q intersect the line l at K and L respectively and line m at N and M respectively.

Since, AB is a straight line and ray KN stands on it, then

∠NKL + ∠NKA = 180∘ (Angles in a linear pair)

⇒110∘ + a = 180∘

⇒a = 180∘ − 110∘ = 70∘

Since, line p || line q and line l is a transversal intersecting them at K and L, then

∠TLB = ∠NKA (Alternate exterior angles)

⇒b = a

⇒b = 70∘

Since, line p || line q and line m is a transversal intersecting them at N and M, then

∠CNK = ∠NML (Corresponding angles)

⇒c = 115∘

Since, CD is a straight line and ray ML stands on it, then

∠NML + ∠LMD = 180∘ (Angles in a linear pair)

⇒115∘ + d = 180∘

⇒d = 180∘ − 115∘ = 65∘

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4