Let the polynomial p be the function of x. The graph of the polynomial has four zeros at 3, -4/3, -1, and 0. Select all the expressions that could represent p.
A. – 2x(x − 3)(x+3)(x + 1)^2
B. 2x(x + 3)(x + 3)(x+1)
C. - x(x − 3)(3x + 4)(2x + 2)
D. - *x(x − 3)(4x + 3)(x + 1)
E. 2x(x − 3)(3x + 4)(x - 1)^2

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

answer: dead jah

step-by-step explanation:

bullet + jah= dead jah

jwjeh; hw; kjhekjhkjhwkejhkw

step-by-step explanation: