What is the minimum angle of rotation (in degrees) that will carry the star onto itself?

When you rotate the regular pentagon \begin{align*}72^\circ\end{align*} about its center, it will look exactly the same. This is because the regular pentagon has rotation symmetry, and \begin{align*}72^\circ\end{align*} is the minimum number of degrees you can rotate the pentagon in order to carry it onto itself.

Step-by-step explanation:

1/800 is the right answer