determine the solution to the system of equations graphed below and explain your reasoning g(x)=3x+2 f(x)=|x-1|+1

(0, 1)

Step-by-step explanation:

To find the solution to these 2 functions, we just set up an equation where they're equal to each other:

3x+2 = |x-1|+1

Then, isolate the absolute value:

3x+1 = |x-1|

Now, to get rid of the absolute value sign, we can set the right-hand side to be the positive or negative version of itself.

First, let's set it to the negative version of itself:

3x+1 = -x+1

4x = 0

x = 0

Then, let's set it to the positive version of itself:

3x+1 = x-1

2x = -2

x = -2

We can now plug the x as 0 and -2 into any of the 2 equations above to find the solution for y:

3(0)+1 = 1, so the first solution will be (0, 1)

3(-2)+2 = -4.

You might be tempted to say that -4 is the y value for the 2nd solution, but notice that |x-1| will never be less than 0, so that would not work. Therefore, x = -2 isn't a solution either, which means it's an extraneous solution.

In conclusion, the solution to these equations is (0, 2).

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