write an equation in slope-intercept form of the line that passes through the points (-2,3) and (2,7)

y = x+5

Step-by-step explanation:

First find the slope

m = ( y2-y1)/(x2-x1)

   = ( 7-3)/(2 - -2)

   ( 7-3)/(2+2)

   4/4

  1

Then slope intercept form is

y = mx+b where m is the slope and b is the y intercept

y = 1*x+b

y = x+b

Substitute a point into the equation

7 = 2+b

7-2 =b

5=b

y = x+5

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0