A ball is thrown upward with an initial velocity of 60 mph. it is thrown from a height of 5 feet. what is the maximum height it reaches?

h = 61.25 m

Step-by-step explanation:

It is given that,

The initial velocity of the ball, v = 60 m/s

It is thrown from a height of 5 feet,

We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

Putting all the values,

.....(1)

For maximum height, put

Put t = 1.875 in equation (1)

So, the maximum height reached by the ball is 61.25 m.

sum= when you add is how much the whole amount is

distance= when you use angles and it means how far it goes

step-by-step explanation:

mujhko hui na