On a coordinate plane, 2 parallelograms are shown. The first parallelogram has points A (negative 4, 4), B (negative 2, 4), C (negative 5, 1), D (negative 2, 1). The second parallelogram has points A prime (negative 2, 5), B prime (1, 5), C prime (negative 3, 2), D prime (0, 2). Which rule represents the translation from the pre-image, ParallelogramABCD, to the image, ParallelogramA'B'C'D'?

T1, –2(x, y)
T1, 2(x, y)
T–2, 1(x, y)
T2, 1(x, y)

4 + 5 7/9= 9 7/9

step-by-step explanation:

answer: do we write it

step-by-step explanation:

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560