Write a linear function with the values (-1,8) and (5,6)

Let the function be y = ax + c.

For (-1,8), 8 = a(-1) + c → 8 = - a + c

For (5,6), 6 = a(5) + c → 6 = 5a + c

Subtract one from abother,

2 = - 6a => - 1/3 = a

Hence, 8 = - 1/3 + c → 23/3 = c

Relation is:

y = (-1/3)x + (23/3)

3y = - x + 23

3y = 23 - x

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5