Two window washers start at the heights shown. One is rising, the other is descending. How long does it take for the two window washers to reach the same height? Explain. 21 ft high

rising 8 in./s

50 ft high

descending 11 in./s

After t seconds, the height of the rising window washer is exactly

nothing feet, and the height of the descending window washer is exactly

nothing feet. Setting these expressions equal to each other and solving for t yields the exact value t

nothing. Rounding to one decimal place, the window washers reach the same height after about

nothing seconds.

(Simplify your answers.)

18.32secs

Step-by-step explanation:

given data:

first washer

21 ft high

rising 8 in./s

second washer

50 ft high

descending 11 in./s

Solution:

initial height of first washer = 21 feet

1feet = 12inches

21 * 12 = 252inches

decending at a pace of 8inch/secs

= 252 + 8x

initial height of second washer

= 50 feet

= 50 * 12

= 600inches

descending at a pace of 11inch/secs

= 600 + 11x

At what time would they meet

252 + 8x = 600 + 11x

collect like terms

8x + 11x = 600 – 252

19x = 348

divide both sides by 19

19x/19 = 348/19

x = 18.32secs

the answer is: the length is 5/6 yards.

give me a or a 5 star rating if this is correct!

step-by-step explanation: