Presto Pizza uses one jar of sauce and one bag of cheese on each large pizza. Each case of sauce has 9 jars. Each case of cheese has 12 bags. What is the fewest number of pizzas they can make if they want to have nothing left over? How many cases of sauce and cheese would they need?

36 pizzas

4 cases of sauce and 3 cases of cheese.

Step-by-step explanation:

In order to solve this problem, we need to find the least common multiple of both of these numbers. We do this by simply multiplying these numbers by each factor of 1 until an equal value is an output. Like so...

9*1 = 9                    12*1 = 12

9*2 = 18                  12*2 = 24

9*3 = 27                  12*3 = 36

9*4 = 36

We can now see that the fewest number of pizzas we can make without having anything left over is 36 pizzas. To do this we would need 4 cases of sauce and 3 cases of cheese.

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )