If ∠1 and ∠2 are complementary, m∠1 = (8x-6)°, and m∠2 = (14x+8)°
URGENT PLEASE HELP

Given : ∠1 + ∠2 = 90° ( complementary )

To Find : The value of x & the two angles .

And , m∠1 = ( 8x - 6 ) ° & m∠2 = ( 14x + 8 )° .

On adding the two Angles their sum will be 90 ° since they are two complementary angles .

⇒ ( 8x - 6 )° + ( 14x + 8 )° = 90° .

⇒ 22x + 2° = 90° .

⇒ 22x = (90 - 2)°

⇒ 22x = 88° .

⇒ x = 88°/22 .

⇒ x = 4° .

Hence the value of x is 4° .

So ,

First angle = 8x - 6 = 8×4-6=32-6=26°Second angle = 14x +8 = 14(4)+8 = 56+8 = 64° .

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