Write an equation in slope-intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-5,8); y=1/5x-3

y = –5x – 17

Step-by-step explanation:

First, we shall determine the slope of the equation y = 1/5x – 3.

The slope of the equation y = 1/5x – 3 can be obtained by comparing the equation with y = mx + c.

This is illustrated below:

y = 1/5x – 3

y = mx + c

Thus, the slope (m) of equation

y = 1/5x – 3 is 1/5

Next, we shall determine the slope of the line perpendicular to the equation as follow:

For perpendicular lines, their slope (m1 and m2) are related as follow:

m1 × m2 = –1

m1 = 1/5

1/5 × m2 = –1

m2/5 = –1

Cross multiply

m2 = 5 × –1

m2 = –5

Therefore, the slope of the line is –5.

Finally, we shall determine the equation of the line as follow:

Coordinate = (–5, 8)

x1 coordinate = –5

y1 coordinate = 8

Slope (m) = –5

y – y1 = m(x –x1)

y – 8 = –5(x – (–5))

y – 8 = –5(x + 5)

y – 8 = –5x – 25

Rearrange

y = –5x – 25 + 8

y = –5x – 17

Therefore, the equation is y = –5x – 17.

answer: huh

step-by-step explanation: