Question 6 1 pts
AJKZ is translated along the vector (1,3) after it is reflected across the y-axis. What are
the coordinates of the final image of point J under this composition of transformations?

I believe that it is (1,-3)

Step-by-step explanation:

Since it isn't reflecting about the x-axis, the x coordinate shouldn't change. The only thing that should be reflected is the y-coordinate, which is why the y changes to a negative. I don't know if I worded that good enough for you, but I believe my answer is correct.

$450

step-by-step explanation:

first, you have to multiply 150x2=300

next, you have to add 150+300= 450

part a: triangles gcb and epb

part b. sides cg and rp are parallel by definition of parallelogram.

angles cgb and e are congruent by being alternate interior angles of parallel lines cut by a transversal. angles gbc and ebp are congruent because they are vertical angles. by aa similarity, the triangles are similar.

part c. since the triangles are similar, the ratios of the lengths of corresponding sides are equal.

calculation of be:

gb/be = cb/bp

(400 ft)/be = 300/200

(400 ft)/be = 3/2

3be = 2 * 400 ft

3be = 800 ft

be = 800/3 ft

calculation of pe:

gc/pe = cb/bp

(350 ft)/pe = 300/200

(350 ft)/pe = 3/2

3pe = 2 * 350 ft

3pe = 700 ft

pe = 700/3 ft