What is the equation of the line that passes through the point (1,3) and has a slope
of 6?

Step-by-step explanation:

The equation of a line is in the form  y=mx+b, where m is slope and b is y-intercept.

The slope is already given.

y = 6x + b

Plug in the values of the coordinate point into the equation to find b.

-3 = 6(-1) + b

-3 = -6 + b

3 = b

The equation of the line is

y = 6x + 3

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)