Taxi company charges $ 8.00 to get into the cab and $ 0.75 per mile. Taxi company B charges $ 6.00 to get into a cab and $ 1.25 per mile. How many miles would the cost be the same for both companies? help me

50 miles

Step-by-step explanation:

Let the miles traveled be x when cost for both taxi A and Taxi B is same

Lets calculate for Taxi A

charge to get in cab = $8

cost of traveling 1 mile = $ 0.75

cost of traveling for x miles = x * cost of traveling 1 mile= $ 0.75x

Total cost for traveling x miles = charge to get in cab +cost of traveling for x mile

Total cost for traveling x miles in Taxi A = $8 + $ 0.75x

Lets calculate for Taxi B

charge to get in cab = $3

cost of traveling 1 mile = $ 1.25

cost of traveling for x miles = x * cost of traveling 1 mile= $ 1.25x

Total cost for traveling x miles = charge to get in cab +cost of traveling for x mile

Total cost for traveling x miles in Taxi B= $3 + $ 1.25x

As we have to find distance when cost for both is same

Thus

Total cost for traveling x miles in Taxi A=Total cost for traveling x miles in Taxi B

8 +  0.75x = 3 +  1.25x

8 - 3 = 1.25x -  0.75x

5 = 0.5x

x = 5/0.5 = 50

Thus, you must travel 50 miles so that cost in both the taxi A and Taxi B is the same

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9