Mathematics, 17.10.2020 08:01, kiasiab17

F(x)=(x-1)^2(x+3)^3(x+1) the zero located at x=1 has a multiplicity of ( blank1 ) and the zero located at x=-3 has a multiplicity of ( blank2 ). The graph of the function will touch, but not cross , the axis at an x-value of (blank3)

blank1: 1,2,3
blank2:1,2,3
blank3: 1 only, -3 and 1 only, -3 only, (-3,-1 and 1),-1 only

Answers: 2

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F(x)=(x-1)^2(x+3)^3(x+1) the zero located at x=1 has a multiplicity of ( blank1 ) and the zero loca...