Which of the following equations have no solution? Check all that apply. A.6x + 1 = 3(2x – 4)
B.2 – 5x = 7x – 12
C.4(3 – x) = 2(6 – 2x)
D.5(x + 2) = 2(x – 4)
E.–4(x + 3) = 4(–x – 1)

6x + 1 = 3(2x – 4), 4(3 – x) = 2(6 – 2x), and −4(x+3)=4(−x−1)

Step-by-step explanation:

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.