A rectangular tract of land in Mathville has the dimensions 4x2 + 3x + 12 and 4x – 2. Another rectangular area of a land in Algebratown has dimensions 5x2 + x – 4 and 2x + 1. A)Find the area of each using the box method in terms of x
B)What is the difference between the area of Mathville and the area of Algebratown?
C)hat is the difference of the areas if x = 9?

Step-by-step explanation:

Area of a rectangle = Length * Width

Given the dimension

Length = 4x2 + 3x + 12

Width = 4x – 2

A) Area =  (4x^2 + 3x + 12)(4x – 2)

Open the parenthesis

= 16x^3-8x^2+12x^2-6x+48x-24

Area of land in Mathville = 16x^3+4x^2+42x-24

For the land in Algebratown

Area =  (5x^2 + x – 4)(2x + 1)

Area = 10x^3+5x^2+2x^2+x-8x-4

Area  = 10x^3+7x^2-7x-4

B) difference between the area of Mathville and the area of Algebratown

= 16x^3+4x^2+42x-24 -(10x^3+7x^2-7x-4)

= 16x^3+4x^2+42x-24 -10x^3-7x^2+7x+4

collect like terms

= 16x^3-10x^3+4x^2-7x^2+42x+7x-24+4

= 6x^3-3x^2+49x-20

C) The difference if x = 9

Substitute x = 9 into the resulting function

A(x) = 6x^3-3x^2+49x-20

A(9) = 6(9)^3-3(9)^2+49(9)-20

A(9) = 2187-243+441-20

A(9) = 2,365

Hence the difference of the areas if x = 9 is 2,365

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05

dont trust me im no expert these losers made me fail a test bro this sucks

step-by-step explanation: