Based on a graph below which sequence of transformation is needed to carry ABCD onto its image A’B’C’D?

Given:

The vertices of ABCD are A(2,3), B(5,6), C(8,6) and D(8,3).

The vertices of A'B'C'D' are A'(-2,6), B'(-5,3), C'(-8,3) and D'(-8,6).

To find:

The sequence of transformation is needed to carry ABCD onto its image A’B’C’D.

Solution:

The vertices of ABCD are A(2,3), B(5,6), C(8,6) and D(8,3).

If figure ABCD translated by the rule, , then

Then the figure rotated 180 degrees clockwise about the origin. So,

So, the required sequence of transformation that is needed to carry ABCD onto its image A’B’C’D is " A translation by the rule and then a 180° clockwise rotation about the origin".

Therefore, the correct option is D.

i think it is c, not positive though

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204