∠A and \angle B∠B are complementary angles. If m\angle A=(6x-8)^{\circ}∠A=(6x−8) ∘ and m\angle B=(5x+21)^{\circ}∠B=(5x+21) ∘ , then find the measure of \angle B∠B.

Use pythagorean’s theorem and find the missing side lengths of the two smaller triangles and add them together
13^2 - 12^2 = 5
15^2 - 12^2 = 9
5+9 = 14
14 is the length of each side of the square
14^2 + 14^2 = 19.8
19.8 is the diagonal length of the inside if the square

6x - 3y = by 2-2x + 6y = 1412x - 6y = 6 (result of multiplying by 2)-2x + 6y = 1410x = 20x = 20/10x = 26x - 3y = 36(2) - 3y = 312 - 3y = 3-3y = 3 - 12-3y = - 9y = -9/-3y = 3solution is (2,3) < ==