Alex bar and Carl are brothers Alex is the oldest and Carl is the youngest the some of the ages of the three brothers is 42 Alex his age is three more than twice Carl's age the difference between Barts in Carl's ages is seven years how old is each brother

Alex = 19 years

Bart's = 15 years

Carl = 8 years

Step-by-step explanation:

Let us represent their ages as

Alex = x

Bart's = y

Carl = z

the sum of the ages of the three brothers is 42

x + y + z = 42

Alex his age is three more than twice Carl's age

x = 2z + 3

The difference between Barts in Carl's ages is seven years

y - z = 7

y = 7 + z

Hence: we Substitute

x + y + z = 42

2z + 3 + 7 + z + z = 42

Collect like terms

2z + z + z + 10 = 42

4z = 42 - 10

4z = 32

z = 32/4

z = 8 years

Hence, Carl = 8 years old

a) y = 7 + z

y = 7 + 8

y = 15 years.

Hence, Bart's is 15 years old

b)x = 2z + 3

x = 2(8) + 3

= 16 + 3

= 19 years

Therefore, Alex is 19 years old.

i think the answer is b