Item 3 Find the distance from point $A$ to $\overleftrightarrow{XZ}$ . Round your answer to the nearest tenth. Triangle X Z A and line X Z are plotted on a coordinate plane. The x-axis ranges from negative 5 to 5, in increments of 1. The y-axis is ranges from negative 5 to 5, in increments of 1. Point X is at ordered pair negative 4 comma negative 3, point Y is at ordered pair 2 comma negative 1.5, point A is at ordered pair 3 comma 3 and point Z is at ordered pair 4 comma negative 1. Angle A Z X is marked with a right angle.

3.2

Step-by-step explanation:

Given the coordinates

X(4, -3)

Y(2, 1.5)

A(3, 3)

Z(4,-1)

We are to find the distance from point A to XZ

First let us get the coordinate XZ

According to vector notation XZ = Z-X

XZ = (4,-1)-(4,-3)

XZ = [(4-4),-1-(-3)]

XZ = (0, 2)

Next is to find the distance from A(3, 3) to XZ(0,2) using the formula for calculating the distance between two points.

D = √(x2-x1)²+(y2-y1)²

x1 = 3, y1 = 3, x2 = 0, y2 = 2

D = √(0-3)²+(2-3)²

D = √9+1

D = √10

D = 3.16

Hence the distance from point A to XZ to nearest tenth is 3.2

do you mean add both of the equations together

because if you do the answer is 10x-5

step-by-step explanation: