URGENT!! A golf ball is hit with an initial velocity of 80 feet per second. H= -16t^2 + 80t.
1) When will the ball reach 48ft?
2) When will the ball reach 110ft?

9514 1404 393

Step-by-step explanation:

A graphing calculator provides a nice solution to this question.

__

1) Put 48 ft in for H and solve for t:

  48 = -16t^2 +80t

  -3 = t^2 -5t

  3.25 = t^2 -5t +6.25 = (t -2.5)^2

  t = 2.5 ±√3.25

The ball will first reach 48 feet at t = 2.5 -√3.25 ≈ 0.697224 seconds.

__

2) The equation tells us the maximum height occurs at t=2.5 seconds. That height is ...

  H = -16(2.5^2) +80(2.5) = 100

The maximum height is 100 feet. The ball will never reach 110 feet.

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation: