10 times the sum of half a number x and 4 is 6

-10.4

Step-by-step explanation:

Assume that the number we are looking for is x.

Now, we want to get 10 times the sum of half the number and 6 and equate this expression to 8. Then we can solve for x

step by step

half the number is 0.5x

the sum of half the number and 6 is 0.5x + 6

10 times the sum of half the number and 6 is 10(0.5x +6)

10 times the sum of half the number and 6 equals 8 is 10(0.5x+6) = 8

Now solve for x

10(0.5x + 6) = 8

5x + 60 = 8

5x = 8 - 60

5x = -52

x = -52/5

x = -10.4

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}