Rathan thinks all factors of even numbers are even. Which explains whether Rathan is correct? He is correct because the product of 2 and any number is even.
He is correct because the product of two even numbers is even.
He is incorrect because the product of an even number and an odd number is even.
He is incorrect because the product of two odd numbers is odd.

answer: i oofed

step-by-step explanation:

oofed=wow

5   1/4   miles per hour

step-by-step explanation:

15   3/4 / 3 = 5   1/4

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)