Aquadratic equation is shown below:
9x2 − 36x + 36 = 0
part a: describe the solution(s) to the equation by just determining the radicand. show your work. (5 points)
part b: solve 2x2 − 9x + 7 = 0 using an appropriate method. show the steps of your work and explain why you chose the method used. (5 points)

A.
radicand or determinant is if have equation
ax^2+bx+c=0
determinant is

if >0, then you have 2 real roots
if =0, then you ahve 1 real root
if <0, then you ahve 2 complex roots

9x^2-36+36
a=9b
b=-36
c=36



we can see that they cancel out and therefor =0
there is 1 real root

B. factor
(2x-7)(x-1)=0
set each to zero
2x-7=0
2x=7
x=7/2

x-1=0
x=1

x=7/2 and 1