Sketch one cycle of the sine curve
y = 2 sin theta

The graph of the given function i.e.

is similar to the graph of the function

but the only change in the graph of the two function is it's amplitude.

The amplitude of the given function is: 2.

Also the period remains the same i.e. 2π.

Hence, we are asked to graph one cycle of the given sine curve.

i.e. we have to plot the graph for 0 ≤ θ ≤ 360°=2π

you have orange juice on wednesday. (idk why this is the answer)

step-by-step explanation:

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!