A rule that airline pilots use to estimate outside temperature in degrees Fahrenheit at an altitude of h thousand feet is to double h, subtract 15, and multiply the result by -1. State a rule for the altitude in feet based upon the outside temperature. At what altitude is outside temperature about -51°F?

The altitude is 33 thousand feet at the given temperature

Step-by-step explanation:

We firstly would need to write out the rule.

We can do this by by doubling h, subtracting 15 and multiply the result by -1

Kindly note that h is in thousands of feet

That would be ;

T = (2 * h - 15) * -1

T = -1(2h - 15)

T = -2h + 15

T = 15 - 2h

So for the altitude in feet at a temperature of - 51 degrees Fahrenheit

We simply substitute the value of -51 for the temperature

So we have;

-51 = 15 - 2h

2h = 15 + 51

2h = 66

h = 66/2

h = 33 thousand feet

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb