Suppose a laboratory has a 38 g sample of polonium-210. the half-life of polonium-210 is about 138 days. how many half-lives of polonium-210 occur in 1104 days? how much polonium is in the sample 1104 days later?
9 ; 0.07 g
8 ; 2,2622 g
8 ; 4.75 g
8 ; 0.15 g

0.15 g of Polonium will be in the sample 1104 days later.

Step-by-step explanation:

The exponential function for decay is,

Where,

y(t) = the amount after time t,

a = initial amount = 38 g

r = rate of decay = 50% = 0.50 (as the sample is getting halved each time)

t = time period = (as we have to convert the time in terms of half lifes)

Putting all the values,

a

step-by-step explanation:

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square