What is the equation of the line that passes through the point (6,-2) and has a slope of -3/2

Let's use the point-slope formula to write the equation of this line.

The point-slope formula is y - y₁ = m(x - x₁).

In the formula, x₁ and y₁ are points and the m is our slope

Now let's substitute.

y + 2 = -3/2(x - 6).

Notice that I put y + 2 above since y - (-2) means y + 2.

Now distribute the -3/2 through the parentheses.

This gives us -3/2x + 9.

Bring down your y + 2 and we have y + 2 = -3/2x + 9.

To put this in standard form, we need to multiply both

sides by 2 because we can't have any fractions.

This gives us 2y + 4 = -3x + 18.

Now move the +4 to the right by subtracting

4 from each side to get 2y = -3x + 14.

Now move your x term to the right by adding 3x to both sides.

So our final answer reads 3x + 2y = 14.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

i dont know men

step-by-step explanation: