Write each interval as an inequality. Then graph the solutions. (–∞,5)

The interval notation given to us means that x is between negative infinity and 5, excluding both endpoints.

So we can write which shortens to

The graph will have an open hole at 5 on the number line, and shading to the left to indicate all points smaller than 5.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐