Find the equation of the line by given two points (-5, -2) and (1, 5). Slope Intercept Form: y = mx +b, m is a slope and b is y value of the y-intercept Slope
formula: m = (y2 - y1)/(x2 - x1)

The equation of the line is 6y = 7x + 23

Step-by-step explanation:

We begin by calculating the slope of the line;

mathematically, the slope is given by;

m = (y2-y1)/(x2-x1)

That would be;

m= (5-(-2))/(1-(-5))

m = 7/6

So the equation becomes;

y = 7/6x + b

We below need to get the value of the y-intercept b

We get this by making a substitution for any of the two points

Let’s say we make the substitution for (-5,-2) in which case y = -2 and x = -5

Thus, we have

-2 = 7/6(-5) + b

-2 = -35/6 + b

b = -2 + 35/6

b = (-12+ 35)/6 = 23/6

So we have;

y = 7/6x + 23/6

let’s multiply through by 6

6y = 7x + 23

what?

step-by-step explanation:

what do you need with. i love quadrants. can you tell me ?

there is no question content here, but you for the free points! : d