the length of a rectangle is 5 less than twice its width. the perimeter is 26 meters. find the dimensions of the rectangle.

Step-by-step explanation:

Let x be the length of rectangle and y its width.

P is the perimeter.

So it is given that length is 5 less than twice its width

x=2y-5 so 2y=x+5

also P=2x+2y=26

lets find x

we know 2y=x+5 we replace 2y on P=2x+2y=26

so 26=2x+(x+5)

26=3x+5

21=3x

x=7

so we have that 2y=x+5 so 2y=7+5=12

y=6

we found

length=7

and

width=6

i'm not entirely sure

step-by-step explanation:

if you ask home depot or lowe's they might be able to you out

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15