In the coordinate plane, the point X (2, 3) is translated to the point x'(5,-2). Under the same translation, the points Y(-1, 1) and Z(5, 5) are translated to Y' and Z', respectively. What are the coordinates of Y' and Z'?

Add steps to solve !! Please

Y'=(2,-4)

Z'=(8,0)

Step-by-step explanation:

X + T = X'

(2,3) + (T) = (5,-2)

T = (3,-5)

Y' = Y + T = (2,-4)

Z' = Z + T = (8,0)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐