If h(x) = 5 + x and (x) = 5. which expression is equivalent to (k-1)(o)? (5+) 1 (5+) 5+ 5+ (5 + x)

(5+x)/x

K*H = 1/x(5+x) or (5+x)1/x which = (5+x)/x because (5+x)1/x = [(5+x)/1] * [1/x] and anything multiplied by one is equal to itself.

yes

step-by-step explanation:

what