What is the remainder when f(x) = 2x^4 + x^3- 8x - 1 is divided by x - 2? A. -23
B. 23
C. -3
D. 3

The remainder when f(x) = 2x^4 + x^3- 8x - 1 is divided by x - 2 is 23

A polynomial is an expression consisting of the operations of addition, subtraction, multiplication of variables.

Polynomial based on degree is linear, quadratic, cubic.

The remainder theorem states that when a polynomial, f(x), is divided by a linear polynomial x - a, the remainder of is to f(a)

Given that f(x) = 2x⁴ + x³ - 8x - 1 is divided by x - 2

x - 2 = 0

x = 2

f(2) = 2(2)⁴ + (2)³ - 8(2) - 1 = 23

Hence The remainder when f(x) = 2x^4 + x^3- 8x - 1 is divided by x - 2 is 23

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By the remainder theorem, dividing by leaves a remainder of , which is

which makes B the correct answer.

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: