Solve 3x2 = −12x − 15. x = −4 ± 2i x = −4 ± i x = −2 ± 2i x = −2 ± i

   x = −2 ± i

Step-by-step explanation:  solution of ax²+bx+c=0 is given by

                 x= ( -b±√(b²-4ac))/2a

            here a=3,b=12 and c=15

          ⇒    x=  (-12±√(12²-4×3×15))/6

           ⇒   x=  (-12±√(144-180))/6

           ⇒   x=  (-12±√(-36))/6

          ⇒    x=  (-12±6i)/6

            ⇒  x=  -2±i

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