How do you write an equation of a line that passes through points (6,5) & (-6,-4)

y = 3/4x + 1/2

Step-by-step explanation:

We can use the formula [ y2-y1/x2-x1 ] to solve for the slope.

-4-5/-6-6

-9/-12

9/12

3/4

Find the y-intercept.

y = 3/4x + b

5 = 3/4(6) + b

5 = 4.5 + b

0.5 = b

y = 3/4x + 1/2

Best of Luck!

First of all, Let's find the slope because we need it on the formula for finding the y-intercept.

From the points given in the question,

Plugging in the above formula,

➝ m = -4 - 5 / -6 - 6

➝ m = -9 / -12

➝ m = 3/4

Now finding the y-intercept

➝ y = mx + b

And if we put in the values from our first point (6, 5) we get

➝ 5 = 3/4 (6) + b

➝ 5 = 9/2 + b

➝ b = 5 - 9/2

➝ b = 1/2

Required equation of the line:

➝ y = 3/4x + 1/2

Carry On Learning !

add 5 subtract 1

step-by-step explanation:

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )