Oct 07, 1:28:22 PM What is the equation of the line that passes through the point (-4, 4) and has a slope of 3/4

y=3/4x+7

Step-by-step explanation:

You want to find the equation for a line that passes through the point (-4,4) and has a slope of 3/4.

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was 3/4. So you can right away fill in the equation for a line somewhat to read:

y=3/4x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(-4,4). When x of the line is -4, y of the line must be 4.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the 3/4 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-4,4).

So, why not plug in for x the number -4 and for y the number 4? This will allow us to solve for b for the particular line that passes through the point you gave!.

(-4,4). y=mx+b or 4=3/4 × -4+b, or solving for b: b=4-(3/4)(-4). b=7.

hope this answers your question sorry it's soo long i just like writing long stuff have a great day!!

details

step-by-step explanation: